• • # Thread: Help teh Ooflendoodle

1. ## Help teh Ooflendoodle

 I'll just post questions I have that I'm stuck on, I would prefer explanations so I can understand this myself and not have to ask in the future. Thanks   Reply With Quote

2.  So I think this one is impossible but I'm probably wrong, how would you factor xsquared-7x-10. If you could give me the explanation and answer that would be great.  Reply With Quote

3.  (X-5)(X-2) X2-7X-10 OK, so you would have 2 X's in each parenthesis like this: (X-_)times(X-_) It's minus for both, because there are 2 minuses. The rest is just trial and error.  Reply With Quote

4.  but that gives me positive ten...  Reply With Quote

5.  Oh! sorry. It's one positive and one negative then. I haven't factored in years. My bad.  Reply With Quote

6.  hmm that also doesn't work because I would have a positive 5 or 2 which wouldn't get me to negative 7 this has to be a typo.  Reply With Quote

7.  That's true. Weird. 10 only factors into 1 and 10 or 5 and 2. it would have to be Xsquared-7+10... Bummer.  Reply With Quote

8.  Oh well I just put impossible thanks for your help though.  Reply With Quote

9.  Yeah. Anytime.  Reply With Quote

10.  If you have a second degree expression you have to factor, one way of always getting the right answer is to set it equal to 0 and solve the resulting equation. x2 - 7x - 10 = 0 Gives the solutions x = (1/2)(7 - sqrt(89)) and x = (1/2)(7 - sqrt(89)) Thus the factorized form is: (x - (1/2)(7 - sqrt(89))) (x - (1/2)(7 - sqrt(89))) (That's (x-s1)(x-s2), with s1 and s2 being the two solutions)  Reply With Quote

11.  Thank you  Reply With Quote

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