there are 4 types of functions: real or imaginary, defined or undefined
y = x : real and defined
y = x^2 / (x - 5) : real but undefined at x = 5
y = √x : imaginary for x < 0, but defined
y = √x / (x + 5) : imaginary and undefined at x = -5
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there are 4 types of functions: real or imaginary, defined or undefined
y = x : real and defined
y = x^2 / (x - 5) : real but undefined at x = 5
y = √x : imaginary for x < 0, but defined
y = √x / (x + 5) : imaginary and undefined at x = -5
I know that.
What I am asking is why there are different answers to the same equation at given steps.
r*24=0
This is only true when r = 0
Yet,
r = 24/0 is undefined. But it is a step in the previous equation.
WHY?
No it isn't, it would be r = 0/24.
:doh:
Brainfart.
:takethatfoo:
Most of this topic has hinged on the original poster's algebra mistake.
If anyone thinks 24/0 = 0 then prove it. Correctly.
In the meantime, read http://en.wikipedia.org/wiki/Division_by_zero first section, please.
There is no substance to this topic, we shall let it die.