I'll just post questions I have that I'm stuck on, I would prefer explanations so I can understand this myself and not have to ask in the future. Thanks :)
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I'll just post questions I have that I'm stuck on, I would prefer explanations so I can understand this myself and not have to ask in the future. Thanks :)
So I think this one is impossible but I'm probably wrong, how would you factor xsquared-7x-10. If you could give me the explanation and answer that would be great.
(X-5)(X-2)
X2-7X-10 OK, so you would have 2 X's in each parenthesis like this: (X-_)times(X-_)
It's minus for both, because there are 2 minuses. The rest is just trial and error.
but that gives me positive ten...
Oh! sorry. It's one positive and one negative then.
I haven't factored in years. My bad.
hmm
that also doesn't work because I would have a positive 5 or 2 which wouldn't get me to negative 7 this has to be a typo.
That's true. Weird. 10 only factors into 1 and 10 or 5 and 2. it would have to be Xsquared-7+10... Bummer.
Oh well I just put impossible thanks for your help though.
Yeah. Anytime.
If you have a second degree expression you have to factor, one way of always getting the right answer is to set it equal to 0 and solve the resulting equation.
x2 - 7x - 10 = 0
Gives the solutions x = (1/2)(7 - sqrt(89)) and x = (1/2)(7 - sqrt(89))
Thus the factorized form is: (x - (1/2)(7 - sqrt(89))) (x - (1/2)(7 - sqrt(89)))
(That's (x-s1)(x-s2), with s1 and s2 being the two solutions)
Thank you