This is a serious question I started thinking about this evening and it turned into quite an existential rabbit hole. |
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This is a serious question I started thinking about this evening and it turned into quite an existential rabbit hole. |
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As I see it, it there is no lower bound on the number without placing restrictions on the "expressions" involved. Specifically, it would seem that any such expression would have to be a map from the set of possible universes to the positive whole numbers. Take any such map, call it θ. Then let φ = θ + 1 so that φ(U) = θ(U) + 1 for some universe U. Then φ(U) > θ(U). |
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Previously PhilosopherStoned
Is it true, though, that a universe with n possible binary states (which seems like the best interpretation of 'universe' in this context) can express a maximum of 2^n numbers (i.e. the maximum binary number with n digits)? |
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Right, absolutely. The reason I went with indexing is because there needs to be some limit placed on the process as I showed in the first paragraph of my first post. Otherwise, the answer to your question is trivially, "No there is no smallest such number." Let's take your example, p(k). |
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Last edited by PhilosopherStoned; 01-17-2011 at 07:07 PM.
Previously PhilosopherStoned
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