Quote Originally Posted by ethen View Post
Ok, just so that I am clear:

1. I would start off by determining nCx. This is done by using the formula n!/(x!*(n-x)!)

2. Once I have this amount, I then apply it to the formula nCx * p^x * q^(n-x)

Now, is this where I stop, or is there a third step (i.e. dividing the amount by the sum of that particular row in Pascal's triangle)?
This (2. in your post) is what gives you the probability for that specific number of hits, provided that you made them randomly.

The whole procedure goes:
1. Assume you guess the orientation of the die by chance alone. This is your null hypothesis. This gives you probability of guessing correctly to be 1/6

2. Decide you will do 30 trials

3. Do 30 trials. Say that you guess correctly 12 times.

4. Calculate the probability of guessing 12 out of 30 times under the null hypothesis. This means you are still assuming you got those guesses by pure luck.
You use the binomial distribution and the above formula for the calculation.

What you do in practice, you actually calculate the probability of getting 12 or more guesses correct by pure chance. This means you calculate probability for getting it right 12 times + probability of getting it 13 + ... + prob. of getting all 30 correct. This is called cumulative probability.
Don't do it by hand, you can use the following applet(cumulative probability will be displayed in the last box after you enter all the parameters):
http://stattrek.com/Tables/Binomial.aspx

5. Interpret the result. For our example (12/30), the cumulative probability is 0.002 or 0.2%. You have a very strong argument for rejecting the null hypothesis. You haven't really proven that you can see the die in your OBE, but you've proven that it's highly unlikely your guesses were due to pure luck.