A 9.6% chance of the results being false means 9.6% of the people with positive results have no cancer. But this is different from 9.6% of people with no cancer having positive results. |
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A 9.6% chance of the results being false means 9.6% of the people with positive results have no cancer. But this is different from 9.6% of people with no cancer having positive results. |
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Last edited by Xei; 11-19-2011 at 12:17 AM.
I would have said that that for cut n, the maximum number of pieces that can be intersected with a straight cut is also n, thus making the maximum number of pieces the nth triangle number. Or the sum of the geometric series 1+2+...n, k=1. |
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Last edited by Photolysis; 11-19-2011 at 12:46 AM.
Right. Stupid me. Thanks for seeing through my problem with word selection. |
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Previously PhilosopherStoned
1. all of the squares (I did it with 10 coins) |
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Last edited by IndieAnthias; 11-19-2011 at 12:54 AM.
I wasn't trying to be sarcastic if that's what you mean... friendship could plausibly be reflexive. |
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Last edited by Xei; 11-19-2011 at 12:56 AM.
7. True. |
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Last edited by Photolysis; 11-19-2011 at 01:03 PM.
Since a person without cancer can only have a 9.6% chance of testing positive, no person without cancer can have a >9.6%> chance of testing positive. If a person is tested positive, which assumes a person is 100% positive, then it follows that with exclusion to this assumption, I may have a < 90.4% chance of having cancer. (This was actually the answer before the "original" one I tried to force. Albeit a bit broad, it's still possible. Who needs such silly complex math when you can make fenced guesses!) I win |
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Last edited by Somii; 11-19-2011 at 02:32 AM.
I stomp on your ideas.
Thanks Xei, this was fun. |
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Impressive stuff Dianeva. The pizza thing is right, the key insight of course that a straight line can only intersect another straight line once. If you fiddle about for a while you can find a nice way of doing it: |
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I think I'm okay at reasoning, but you like to point out how horrible I am at it. Actually you like to point out how horrible everyone is at it. |
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DILDs: A Lot
Okay my final answers for all except #6 which I still haven't looked at, along with the explanations. |
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I'm often wrong on what? Opinions? |
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Last edited by DeeryTheDeer; 11-19-2011 at 10:46 PM.
DILDs: A Lot
I just realized that (5) is 2 and blue. What the hell was I thinking. I didn't even make a mistake before with the wording. I translated it in my mind to [even number] --> [red other side] and realized it didn't have to be the other way around, but still made that mistake somehow. The 2 has to be flipped to make sure it's red on the other side, and the blue has to be flipped to make sure its other side is an odd number. No need to comment on that unless for some reason it's wrong. |
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Last edited by Dianeva; 11-19-2011 at 10:21 PM.
Ah, I should have just tried to do this, this is how I imagined doing it. |
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Last edited by Wayfaerer; 11-19-2011 at 09:59 PM.
Ok, I realize for 5 flipping the red card may additionally confirm the claim but isn't necessary. |
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I thought the meat was in figuring out the odd factor thing. The squares thing is (imo)just a cute way to use a well known fact from number theory to cover it up and make it look cool. I hate it when people do that. |
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Previously PhilosopherStoned
I'm gonna say only the first one is still heads up, coz it never gets flipped and the rest flip on to tails. |
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Last edited by tommo; 11-20-2011 at 03:03 AM.
Don't be mean to Deery. His avatar his cool. |
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Last edited by Somii; 11-20-2011 at 03:05 AM.
I stomp on your ideas.
Apparently I suck... the only one I got without looking was the cards one... |
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April Ryan is my friend,
Every sorrow she can mend.
When i visit her dark realm,
Does it simply overwhelm.
It's late and I'm tired so I only attempted 2, think it's 22. The sequence formed is just adding one more each time as each time the wire can go through one more previous cut. So you get the sequence 1 2 4 7 11 16 22. Think that works out as, (n(n+1))/2 +1. |
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1.To be flipped at the end it must have an odd number of divisors not including 1, and since in non squares the divisors can all be paired off and must be even, all numbers that are not square or prime must end up being flipped an odd number of times and so tails up (squares cant be paired off as one number would be paired with itself and in this coin game you are only going through each number once.). All primes must be tails up as they are only flipped once. So all that is left is squares. That argument doesn't quite feel right, think I've done something stupid but I'm going to go with all squares heads up. |
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Last edited by Stubert; 11-22-2011 at 12:34 AM.
Does anybody have any more cool puzzles; especially like questions 1, 2 and 7? |
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