Originally Posted by Xei
Are you sure you didn't get that backwards..?
Not really sure what you mean.
The mass of a body still only ever resists it's acceleration though,
a=F/m
unless it's accelerated by another body's gravitational field I guess...
Originally Posted by Xei
The force is proportional to both the other object's mass and its mass too.
I'm being told not though lol
Originally Posted by Xei
acceleration of an object due to a massive body is independent of its mass
Originally Posted by Xei
You've got some large object with mass, and then another one which you're dropping. If you double the mass of the one you're dropping, this doubles the force applied to it, but also means that it requires double the force to accelerate it by the same amount, so the acceleration (and the entire motion) is unchanged.
According to general relativity, gravity is an inertial force, not an interaction force, mass does not resist it. The stronger the warping between two objects, the stronger the inertial force, mass does not balance anything out.
Originally Posted by Xei
The more intuitive way to think of it is to remember that objects are just systems of particles, all of which are affected by gravity. So say you have two identical objects. First you drop them next to each other. Then you glue them together and drop them. Clearly nothing will change the second time; it'll fall just as fast as if there were no glue.
Sure two identical objects would fall at the same rate, but my point is that it's hard to imagine two objects with two different space-time warping contributions would fall at the same rate if the inertial force of gravity is independent of mass. I'm not interested in treating the objects with less mass as idealized "test particles" that have no effect on gravity because I'm interested in reality lol
|
|
Bookmarks