No, I don't think so.
If I start at one edge and run to the other (maximising the distance he must go, while also minimising the distance I must go), say it is 10m diameter.
He will have to go (c= pi X d)/2 which is 15.7m and I will go 10m, obviously.
At 1m p/s it will take me 10 seconds to get to the other side. At 4m p/s it will take him 3.9 seconds.
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